栈数组与栈链表数据结构的C语言代码实现
栈数组
#include<stdio.h>#include<stdlib.h>#include<string.h>#define maxn 10000//结点设计typedef struct stack{ int data[maxn]; int top;}stack;//创建stack *init(){ stack *s=(stack *)malloc(sizeof(stack)); if(s==NULL){ printf("分配内存空间失败"); exit(0); } memset(s->data,0,sizeof(s->data)); //memset操作来自于库文件string.h,其表示将整个空间进行初始化 //不理解可以查阅百度百科https://baike.baidu.com/item/memset/4747579?fr=aladdin s->top=0; //栈的top和bottom均为0(表示为空) return s;}//入栈pushvoid push(stack *s,int data){ s->data[s->top]=data; s->top++;}//出栈popvoid pop(stack *s){ if(s->top!=0){ s->data[s->top]=0; //让其回归0模拟表示未初始化即可 s->top--; }}//模拟打印栈中元素void print_stack(stack *s){ for(int n=s->top-1;n>=0;n--){ printf("%d\t",s->data[n]); } printf("\n"); //习惯性换行}int main(){ stack *s=init(); int input[5]={11,22,33,44,55}; //模拟五个输入数据 for(int i=0;i<5;i++){ push(s,input[i]); } print_stack(s); ///////////// pop(s); print_stack(s); return 0;} |
栈链表:
an#include <stdio.h>#include <stdlib.h>//栈的结点设计//单个结点设计,数据和下一个指针typedef struct node { int data; struct node *next;} Node;//利用上面的结点创建栈,分为指向头结点的top指针和计数用的counttypedef struct stack { Node *top; int count;} Link_Stack;//创建栈Link_Stack *Creat_stack(){ Link_Stack *p; //p = new Link_Stack; p=(Link_Stack*)malloc(sizeof(Link_Stack)); if(p==NULL){ printf("创建失败,即将退出程序"); exit(0); } p->count = 0; p->top = NULL; return p;}//入栈 pushLink_Stack *Push_stack(Link_Stack *p, int elem){ if (p == NULL) return NULL; Node *temp; temp=(Node*)malloc(sizeof(Node)); //temp = new Node; temp->data = elem; temp->next = p->top; p->top = temp; p->count++; return p;}//出栈 popLink_Stack *Pop_stack(Link_Stack *p){ Node *temp; temp = p->top; if (p->top == NULL) { printf("错误:栈为空"); return p; } else { p->top = p->top->next; free(temp); //delete temp; p->count--; return p; }}//遍历栈:输出栈中所有元素int show_stack(Link_Stack *p){ Node *temp; temp = p->top; if (p->top == NULL) { printf(""); printf("错误:栈为空"); return 0; } while (temp != NULL) { printf("%d\t", temp->data); temp = temp->next; } printf("\n"); return 0;}int main(){ //用主函数测试一下功能 Link_Stack *p; p = Creat_stack(); int n = 5; int input[6] = {10,20,30,40,50,60}; /////////////以依次入栈的方式创建整个栈////////////// for(int i=0;i<n;i++){ Push_stack(p, input[i]); } show_stack(p); ////////////////////出栈/////////////////////// Pop_stack(p); show_stack(p); return 0;} |
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