javascript面试题:如何在 JS 中“深冻结”对象?
73. 如何在 JS 中“深冻结”对象?
如果咱们想要确保对象被深冻结,就必须创建一个递归函数来冻结对象类型的每个属性:
没有深冻结
let person = {
name: "Leonardo",
profession: {
name: "developer"
}
};
Object.freeze(person);
person.profession.name = "doctor";
console.log(person); //output { name: 'Leonardo', profession: { name: 'doctor' } }
复制代码
深冻结
function deepFreeze(object) {
let propNames = Object.getOwnPropertyNames(object);
for (let name of propNames) {
let value = object[name];
object[name] = value && typeof value === "object" ?
deepFreeze(value) : value;
}
return Object.freeze(object);
}
let person = {
name: "Leonardo",
profession: {
name: "developer"
}
};
deepFreeze(person);
person.profession.name = "doctor"; // TypeError: Cannot assign to read only property 'name'
作者:前端小智
链接:https://juejin.im/post/5e1faa3d51882520a167df0e
来源:掘金
著作权归作者所有。商业转载请联系作者获得授权,非商业转载请注明出处。
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