zip()函数将可迭代对象作为参数，并打包成元组，返回的是一个个zip对象，可以使用list或dict转换返回结果，使用*zip可以将打包的对象分解成列表文章源自菜鸟学院-https://www.cainiaoxueyuan.com/bc/9163.html
>>> l=[1,2,3,4]
>>> keys=['a','b','c','d']
>>> zip(keys,l)
<zip object at 0x000001E0AFA327C8>
>>> dict(zip(keys,l))
{'a': 1, 'b': 2, 'c': 3, 'd': 4}
>>> list(zip(keys,l))
[('a', 1), ('b', 2), ('c', 3), ('d', 4)]
# 若参数列表的长度不一样，则以最短长度为准
>>> m=[1,2,3]
>>> list(zip(keys,m))
[('a', 1), ('b', 2), ('c', 3)]
# 分解zip
>>> a1,a2=zip(*zip(keys,l))
>>> a1
('a', 'b', 'c', 'd')
>>> a2
(1, 2, 3, 4)
>>>
将二维列表转成json文章源自菜鸟学院-https://www.cainiaoxueyuan.com/bc/9163.html
>>> import json >>> l=[[1,2,3,4],[5,6,7,8],[9,10,11,12]] >>> keys=['a','b','c','d'] >>> list_json=[dict(zip(keys,item)) for item in l] # indent缩进量，ensure_ascii=False支持中文 >>> str_json=json.dumps(list_json,indent=2, ensure_ascii=False) >>> print(str_json) [ { "a": 1, "b": 2, "c": 3, "d": 4 }, { "a": 5, "b": 6, "c": 7, "d": 8 }, { "a": 9, "b": 10, "c": 11, "d": 12 } ]